Integral Test
Let {an}n=1∞ be a sequence of positive terms. Suppose there is a positive integer N such that for all n≥N, an=f(n), where f(x) is a:
- Decreasing,
- Continuous,
- Positive,
function of x. Then, the series n=N∑∞an and the integral ∫N∞f(x)dx both converge or both diverge.
In other words, the Integral Test states that if f(x) is the continuous function corresponding to an and f(x) is decreasing, continuous, and positive, then n=N∑∞an and ∫N∞f(x)dx either both converge or both diverge.
Keep in mind the following:
- If the series and integral are convergent, they are not necessarily equal.
- The integral need only be decreasing eventually on the interval.
- The Integral Test can be used to prove the conclusion of the p-Series Test.
Example 1
Determine the convergence/divergence of the series n=1∑∞n+21 using the Integral Test.
View Answer
Diverges
Example 2
Determine the convergence/divergence of the series n=1∑∞n2+48n using the Integral Test.
View Answer
Diverges
Example 3
Determine the convergence/divergence of the series n=1∑∞n2+1−10 using the Integral Test.
View Answer
Inconclusive (terms are not positive)
Example 4
Determine the convergence/divergence of the series n=1∑∞ne−n2 using the Integral Test.
View Answer
Converges
Example 5
Show that the p-Series n=1∑∞np1 converges for p>1 and diverges for p≤1 using the Integral Test (assuming p is a positive real constant).
View Answer
Evaluate ∫1∞xp1dx:
- For p>1, the integral converges.
- For p≤1, the integral diverges.
Thus, the series follows the same behavior as the integral.
Remainder Estimation
For some convergent series, such as geometric series or telescoping series, we can find the sum of the series. For most convergent series, however, we cannot easily find the sum. Nevertheless, we can estimate the sum by adding the first n terms to get the partial sum Sn, but we need to know how far off Sn is from the total sum S.
If a series ∑an is known to be convergent by the Integral Test, the remainder Rn measuring the difference between the total sum S and its nth partial sum Sn is given by:
Rn=S−Sn=an+1+an+2+an+3+⋯. If {an}n=1∞ is a sequence of positive terms with ak=f(k), where f(x) is a continuous, positive, decreasing function for x≥n and k=1∑∞ak converges to S, then the remainder Rn=∣S−Sn∣ satisfies:
∫n+1∞f(x)dx≤Rn≤∫n∞f(x)dx. Example 6
Estimate the sum S of the series n=1∑∞n21 with n=10.